There are many different ways to find out the duplicates in a List or count of duplicates in a List object. Three best ways have been implemented in the below sample class. I suggest to go with 2nd sample, when there is a requirement in your project.
package in.javatutorials;
import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.HashSet;
import java.util.List;
import java.util.Map;
import java.util.Set;public class CountOfDuplicatesInList {
public static void main(String[] args) {
List<String> list = new ArrayList<String>();
list.add(“a”);
list.add(“b”);
list.add(“c”);
list.add(“d”);
list.add(“b”);
list.add(“c”);
list.add(“a”);
list.add(“a”);
list.add(“a”);// Find out the count of duplicates by passing a String – static way
System.out.println(“\n Output 1 – Count ‘a’ with frequency”);
System.out.println(“a : ” + Collections.frequency(list, “a”));// Find out the count of duplicates using Unique values – dynamic way
System.out.println(“\n Output 2 – Count all with frequency”);
Set<String> uniqueSet = new HashSet<String>(list);
for (String temp : uniqueSet) {
System.out.println(temp + “: ” + Collections.frequency(list, temp));
}// Find out the count of duplicates using Map – Lengthy process
System.out.println(“\n Output 3 – Count all with Map”);
Map<String, Integer> map = new HashMap<String, Integer>();for (String temp : list) {
Integer count = map.get(temp);
map.put(temp, (count == null) ? 1 : count + 1);
}
for (Map.Entry<String, Integer> entry : map.entrySet()) {
System.out.println(“Key : ” + entry.getKey() + ” Value : ”
+ entry.getValue());
}
}
}
Other Useful Links:
Avoid nested loops using Collection Framework in Java
Replace special characters in a String using java
Singleton Design pattern in JAVA
Convert Array to Vector in Java